Find a,p,q and b if
`A={:[(a-3,6,b-q),(1,5,9)]={:[(0,2p-q,-4),((q-p)/(2),5,a+b)]:}`.

The following are the steps in finding the matrix B, if B + ({:(2, 3), (4, 5):}) = ({:(5, 4), (3, 2):}) . Arrange them in sequential order. (A) therefore ({:(p, q), (r, s):}) + ({:(2, 3), (4, 5):}) = ({:(5, 4), (3, 2):}) (B) Let B = ({:(p, q), (r, s):}) (C) ({:(p+2, q+3), (r+4, s+5):}) = ({:(5, 4), (3, 2):}) (D) P + 2 = 5, q + 3 = 4, r+ 4 = 3, s + 5 = 2 rArr p = 3, q = 1, r = -1, s = -3 (E) therefore B = ({:(3, 1), (-1, -3):})

If A={:[(p,2),(-4,-5)]:},B={:[(q,r-s),(r,-5)]:}" and A=B. Find"{:[(p,q),(r,s)]:} , if the trace of A+B=-2.

If a+b=p and ab=q, show that (1)/(a^(3))+(1)/(b^(3))=(p^(3))/(q^(3))-3(p)/(q^(2))

If P=[{:(3,4),(2,-1),(0,5):}]" and "Q=[{:(7,-5),(-4," "0),(2," "6):}] , verify that (P+Q)'=(P'+Q').

If -3+5i is a root of the equation x^2+p x+q=0 , then the ordered pair (p ,q) is (p ,q in R) (-6,34) (b) (6,34) 34 ,-6) (d) 34 ,6)

Let alpha,beta be the roots of the equation x^2-p x+r=0a n dalpha//2,2beta be the roots of the equation x^2-q x+r=0. Then the value of r is 2/9(p-q)(2q-p) b. 2/9(q-p)(2q-p) c. 2/9(q-2p)(2q-p) d. 2/9(2p-q)(2q-p)

If P=(1,2,3,4,5,6,7) and Q=(2,5,8,9) , then find P-Q.

The vertices of triangle are A(-5,3),B(p-1) and C(6,q). If the centroid of the DeltaABC is (1,-1) , then the values of p and q are (i) p=-2,q=5 (ii) p=2,q=-5 (iii) p=3,q=5 (iv) p=-5,q=2