" (i) "lim_(x rarr(pi)/(2))(sec x-tan x)

lim_(x rarr((pi)/(2)))(1-sin x)tan x=

lim_ (x rarr (pi) / (2)) (sec x-tan x) / (pi-2x)

The value of (lim_(x rarr pi/2)(sec x-tan x) is a.1b*0c.2d.-1

the value of lim_(x rarr(pi)/(2))(sec theta-tan theta)

lim_(x rarr(pi)/(2))(1+cos x)^(2sec x)

Evaluate the following limits: lim_(x rarr((pi)/(2)))tan x

lim_(x rarr (pi)/(2)) ((1 - tan x//2)(1-sin x))/((1+tan x//2) (pi - 2x)^(3)) is :

The value of lim_(x rarr(pi)/(3))((tan^(3)x-3*tan x)/(cos(x+(pi)/(6))))

The value of lim_(x rarr(pi)/(3))(tan^(3)x-3tan x)/(cos(x+(pi)/(6)))is:

lim_(x rarr2)(2^(x)+2^(3-x)-6)/(sqrt(2^(-x))-2^(1-x))-lim_(x rarr(pi)/(3))(tan^(3)x-3tan x)/(cos(x+(pi)/(6)))> then the greatest value of a is