Home
Class 12
CHEMISTRY
A gaseous hydrocarbon requires 6 times i...

A gaseous hydrocarbon requires 6 times its own volume of `O_(2)` for complete oxidation and produces 4 times its volume of `CO_(2)`. What is its formula ?

Text Solution

Verified by Experts

The balanced equation for combustion
`C_(x) H_(y)+(x+(y)/(4))O_(2) rarr xCO_(2) +(y)/(2) H_(2)O`
1 volume `(x+(y)/(4))` volume
`therefore x+(y)/(4)=6` (by equation)
or 4x+y=24
Again x=4 since evolved `CO_(2)` is 4 times that of hydrocarbon
`therefore 16 +y=24" or "y=8 therefore` formula of hydrocarbon `C_(4)H_(8)`
Promotional Banner

Topper's Solved these Questions

  • GASEOUS STATE

    FIITJEE|Exercise SOLVED PROBLEMS (SUBJECTIVE)|17 Videos

  • GASEOUS STATE

    FIITJEE|Exercise SOLVED PROBLEMS (OBJECTIVE)|20 Videos

  • ENVIRONMENTAL CHEMISTRY

    FIITJEE|Exercise ASSIGNMENT PROBLEMS (OBJECTIVE) LEVEL -II (MULTIPLE CORRECT QUESTIONS)|20 Videos

  • GENERAL ORGANIC CHEMISTRY

    FIITJEE|Exercise SINGLE INTEGER ANSWER TYPE QUESTIONS|14 Videos

Similar Questions

Explore conceptually related problems

The formula of a gaseous hydrocarbon which requires 6 times of its own volume of O_2 for complete oxidation and produces 4 time its own volume of CO_2 is C_(x)H_(y) . The value of y is _________

10 mL of a certain hydrocarbon require 25 mL of oxygen for complete combustion and the volume CO_(2) of product is 20 mL. What is the formula of hydrocarbon ?

30mL of a gaseous hydrocarbon requires 90mL of O_(2) for complete oxidation, 60mL of CO_(2) gas is formed in the process. The molecular formula of the hydrocarbon will be:

10 ml of hydrocarbon requries 55 ml of oxygen for complete combustion producing 40 ml of CO_(2) . The formula of the hydrocarbon is:

Pd can adsorb 900 times its volume of hydrogen. This is called :-

A gaseous alkane was exploded with oxygen. The volume of O_(2) for complete combustion to CO_(2) formed was in the ratio of 7:4 . The molecular formula of alkane is: