The sealed containers of the same capacity and at the same temperature are filled with 44 g of `H_(2)` in one and 44 g of `CO_(2)` in the other. If the pressre of carbon dioxide in the second container is 1 atm. That of hydrogen in the first container would be.

Options

A. 1 atm
B. 10 atm
C. 22 atm
D. 44 atm

Explanation

`(P_(1)V_(1))/(P_(2)V_(2))=(n_(1)RT_(1))/(n_(2)RT_(2))=(n_(1)T_(1))/(n_(2)T_(2))`
As, `V_(1) =V_(2) & T_(1) =T_(2)`
`(P_(1))/(P_(2))=(n_(1))/(n_(2))`
`(P_(H_(2)))/(P_(co_(2)))=(n_(H_(2)))/(n_(co_(2)))`
`(P_(H_(2)))/(1)=(44//2)/(44//44)=22` atm
Hence, (C ) is the correct answer.