Home
Class 12
CHEMISTRY
When 3.2 g S is vaporized at 450^(@)C an...

When 3.2 g S is vaporized at `450^(@)C and 723` mm pressure, the vapours occupy a volume of 780 mL What is the molecular formula of S vapours ?

Text Solution

Verified by Experts

Given, P =2 atm, T=270=273=543 K
`w_(CO_(2))=2xx1.53g,m_(CO_(2))=44`
`because PV=(w//m)RT`
`2xxV=[(2xx1.53)//44]xx0.0821xx543`
`therefore V=1.55` litre
Promotional Banner

Topper's Solved these Questions

  • GASEOUS STATE

    FIITJEE|Exercise Exercise-3|2 Videos

  • GASEOUS STATE

    FIITJEE|Exercise Exercise-4|2 Videos

  • GASEOUS STATE

    FIITJEE|Exercise Exercise-1|2 Videos

  • ENVIRONMENTAL CHEMISTRY

    FIITJEE|Exercise ASSIGNMENT PROBLEMS (OBJECTIVE) LEVEL -II (MULTIPLE CORRECT QUESTIONS)|20 Videos

  • GENERAL ORGANIC CHEMISTRY

    FIITJEE|Exercise SINGLE INTEGER ANSWER TYPE QUESTIONS|14 Videos

Similar Questions

Explore conceptually related problems

When 3.2g sulphur is vaporised at 450^(@)C and 723mmHg pressure,the vapours occupy a volume of 780ml what is the molecular formula of S-vapour

When 3.2g of sulphur is vapourised at 450^(@)C and 723 mm pressure , the vapours occupy a volume of 780ml. What is the molecular formula of sulphur vapours under these conditions? Calculate the vapour density also.

When 3.2 gm of sulphur is vapourized at 450^(@)C and 723 mm pressure, the vapour occupies a volume of 780 m, what is the formula for the sulphur under these conditions?

At 450^(@)C and 723 mm pressure, 3.2 g of sulphur vapours occupy a volume of 780 mL. What is the molecular formula under these conditions?

A gas occupies 300mL at 127%^(@) C and 730 mm pressure What would be its volume as STP ? .

3.2 g of S is heated to occupy a volume of 780 ml at 450^(@)C and 723 mm pressure. Formula of sulphure is

The density of phosphorus vapour at 310^(@)C and 775 torr is 2.64 g dm^(-3) . What is the molecular formula of phosphorus ?