Home
Class 12
CHEMISTRY
The value of PV for 5.6 litres of an ide...

The value of PV for 5.6 litres of an ideal gas is.. RT, at N.T.P.

Text Solution

Verified by Experts

apply `=(pV)_(max) =nRT_("max")`
Promotional Banner

Topper's Solved these Questions

  • GASEOUS STATE

    FIITJEE|Exercise ASSIGNMENT PROBLEMS (SUBJECTIVE) LEVEL-2|9 Videos

  • GASEOUS STATE

    FIITJEE|Exercise ASSIGNMENT PROBLEMS (OBJECTIVE) LEVEL-I|50 Videos

  • GASEOUS STATE

    FIITJEE|Exercise Exercise-7|2 Videos

  • ENVIRONMENTAL CHEMISTRY

    FIITJEE|Exercise ASSIGNMENT PROBLEMS (OBJECTIVE) LEVEL -II (MULTIPLE CORRECT QUESTIONS)|20 Videos

  • GENERAL ORGANIC CHEMISTRY

    FIITJEE|Exercise SINGLE INTEGER ANSWER TYPE QUESTIONS|14 Videos

Similar Questions

Explore conceptually related problems

The value of PV for 5.6 L of an ideal gas is ……… RT at NTP .

The equation of state for n moles of an ideal gas is PV=nRT, where R is a constant. The SI unit for R is:

The equation of state of n moles of an ideal gas is PV=nRT, where R is a constant. The SI unit for R is :

From the relation PV = RT, calculate the value of the constant R for one gram mole of an ideal gas (in cal//K )

If the weight of 5.6 litres of a gas at N.T.P. is 11 gram. The gas may be :

The ideal gas equation for 1 mol of ideal gas is PV = nRT graph between P and T at constant volume, i.e. isochores are plotted as under Which of the following order of volume is correct ?