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The rate of change in concentration of C...

The rate of change in concentration of C in the reaction `2A+B to 2C +3D` was `1.0 molL^(-1)S^(-1)`. Calculate the reaction rate as well as rate of change of concentration of A,B, and D

Text Solution

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We have,
`-(1)/(2)(d[A])/(dt)=(-d[B])/(dt)=(1)/(2)(d[C ])/(dt)=(1)/(3)(d[D])/(dt)=` rate of reaction
`:. (d[C ])/(dt)=1.0 mol L^(-1)sec^(-1)`
`:.-(d[A])/(dt)=(d[C])/(dt)=1.0molL^(-1)sec^(-1)`
`-(d[B])/(dt)=(1)/(2)(d[C])/(dt)=(1)/(2)=0.5molL^(-1)sec^(-1)`
`(d[D])/(dt)=(3)/(2)(d[C])/(dt)=(3)/(2)xx1=1.5mol L^(-1)sec^(-1)`
Rate `=(1)/(2)(d[C])/(dt)=(1)/(2)xx1=0.5molL^(-1)sec^(-1)`
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