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Freezing point of benzene is 278.4K and ...

Freezing point of benzene is 278.4K and heat of fusion of benzene is 10.042 KJ/mol. Acetic acid exists partly as dimer in benzene solution. The freezing point of 0.02mol fraction of acetic acid in benzene is 277.4K.
The molal cryoscopic constant of benzene in K `"molality"^(-1)` is

A

`4.0`

B

5.6

C

4.5

D

`5.0`

Text Solution

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The correct Answer is:
D
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The freezing point of 0.02 mole fraction acetic acid in benzene is 277.4 K . Acetic acid exists partly as dimer. Calculate the equilibrium constant for dimerization. The freezing point of benzene is 278.4 K and the heat the fusion of benzene is 10.042 kJ mol^(-1) . Assume molarity and molality same.

Read the following paragraph and answer the question given below: Freezing point of benzene is 278.4K and heat of fusion of benzene is 10.042 KJ/mol. Acetic acid exists partly as dimer in benzene solution. The freezing point of 0.02 mol fraction of acetic acid in benzene is 277.4 K. The degree of dimerisation of acetic acid in benzene is

Knowledge Check

  • Read the following paragraph and answer the question given below: Freezing point of benzene is 278.4K and heat of fusion of benzene is 10.042 KJ/mol. Acetic acid exists partly as dimer in benzene solution. The freezing point of 0.02 mol fraction of acetic acid in benzene is 277.4 K. The molal cryoscopic constant of benzene in K "molality"^(-1) is

    A
    `4.0`
    B
    5.6
    C
    4.5
    D
    `5.0`
  • Freezing point of benzene is 278.4K and heat of fusion of benzene is 10.042 KJ/mol. Acetic acid exists partly as dimer in benzene solution. The freezing point of 0.02mol fraction of acetic acid in benzene is 277.4K. The degree of dimerisation of acetic acid in benzene is

    A
    0.24
    B
    0.72
    C
    0.48
    D
    0.64
  • Read the following paragraph and answer the question given below: Freezing point of benzene is 278.4K and heat of fusion of benzene is 10.042 KJ/mol. Acetic acid exists partly as dimer in benzene solution. The freezing point of 0.02 mol fraction of acetic acid in benzene is 277.4 K. The equilibrium constant for dimerisation of acetic in benzene is

    A
    2.4
    B
    3.39
    C
    2.42
    D
    2.56
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    Freezing point of benzene is 278.4K and heat of fusion of benzene is 10.042 KJ/mol. Acetic acid exists partly as dimer in benzene solution. The freezing point of 0.02mol fraction of acetic acid in benzene is 277.4K. The equilibrium constant for dimerisation of acetic acid in benzene is

    Acetic acid exist asa dimer in benzene solution. This is due to

    Acetic acids exists in dimer state in benzene due to

    Acetic acid exist in dimer state in benzene due to

    Mole fraction of acetic acid in benzene given a solution having freezing point 277.4K. Freezing point of benzene is 278.4K and heat of fusion of benzene is 10.042 kJ/mol. If molarity of solution is equal to molality, and acetic acid is found in equilibrium with it dimmer, than answer the following based upon above data. K_(f) for benzene is