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Freezing point of benzene is 278.4K and ...

Freezing point of benzene is 278.4K and heat of fusion of benzene is 10.042 KJ/mol. Acetic acid exists partly as dimer in benzene solution. The freezing point of 0.02mol fraction of acetic acid in benzene is 277.4K.
The molal cryoscopic constant of benzene in K `"molality"^(-1)` is

A

`4.0`

B

5.6

C

4.5

D

`5.0`

Text Solution

Verified by Experts

The correct Answer is:
D
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Acetic acids exists in dimer state in benzene due to

The freezing point of 0.02 mole fraction acetic acid in benzene is 277.4 K . Acetic acid exists partly as dimer. Calculate the equilibrium constant for dimerization. The freezing point of benzene is 278.4 K and the heat the fusion of benzene is 10.042 kJ mol^(-1) . Assume molarity and molality same.