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When I is oxidised by MnO(4), in alkalin...

When I is oxidised by `MnO_(4)`, in alkaline medium, I converts into

A

` I0_(3) `

B

`I_(2)`

C

`IO_(4)`

D

`IO`

Text Solution

Verified by Experts

The correct Answer is:
B
`2K_(2)MnO_(4) + 2KOH to 2K_(2)MnO_(4) + H_(2)O +O`
`2K_(2),MnO_(4), +2H_(2),O to 2MnO_(2), +4KOH+ 20`
`2KMnO_(4), +H_(2)Ooverset(alkaline) to 2MnO_(2) + 2KOH+3[O]`
`KI+[O] to KIO_(3)`
2KMnO_(4) +KI+H_(2)O to 2KOH + 2MnO_(2) +KIO_(3)`
Honce, (B) is the correct answer
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