Calculate the enthalpy of combustion of benzene (l) on the basis of the following data:
(i) Resonance energy of benzene (l) = -152 kJ/mol.
(ii) Enthalpy of hydrogenation of cyclohexene (l) = -119 kJ/mol.
(iii) `DeltaH_(l)^(@)` of `H_(2)O` (l) = -285.8 kJ/mol.
(iv) `DeltaH_(l)^(@)` of `H_(2)O` (l) = -285.8 kJ/mol`
`(v) `DeltaH_(l)^(@)` of `CO_(2)(g) = -393.5` kJ/mol.

Explanation

`DeltaH_(1)^(@)` (benzene) =-156 + 357 = 201 kJ/mol.
Resonance energy `=DeltaH_(l)^(@) - DeltaH_(l)^(@)`
`DeltaH_(l)`(benzene) = -152 + 201 = 49 kJ/mol.
Actual + `15/2 O_(2)(l) to 6CO_(2)(g) + 3H_(2)O(l)`.
`DeltaH^(@) = 6DeltaH_(l)^(@) CO_(2)(g) + 3DeltaH_(l)^(@)H_(2)O(l) - DeltaH_(l)^(@)` (benzene)
`=6(-393.5) + 3(-285.8)-49`
`=-3267.4` kJ/mol.