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MnO(4)^(-) + 8H^(+) + 5e to Mn^(2+) + 4H...

`MnO_(4)^(-) + 8H^(+) + 5e to Mn^(2+) + 4H_(2)O`
`Fe^(3+) + e to Fe^(2+) , E^(@) = +1.51` V
`Cl_(2) + 2e to 2Cl^(-), E^(@) = +0.77` V
`Cl_(2) + 2e to 2Cl^(-), E^(@) =+1.36` V
`Ce^(4+) + e to Ce^(3+), E^(@) = 1.76`
Choose the incorrect statement among the following:

A

`MnO_(4)^(-)` is a sufficiently strong oxidant in acidic solution (pH=0) to oxidise `Fe^(2+)` ion.

B

`Fe^(2+)` ion cannot be titrated against standard `KMnO_(4)` solution is the medium is made acidic (pH=0) by adding HCl.

C

`MnO_(4)` ion cannot oxidise `Ca^(3+)` in acidic medium (pH=0)

D

`Fe^(2+)` cannot be titrated against standard `KMnO_(4)` solution in acid medium (pH=0 in presence of `Ce^(3+)` ion.

Text Solution

Verified by Experts

The correct Answer is:
D
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MnO_(4)^(-) + 8H^(+) + 5e^(-) rightarrow Mn^(2+) + 4H_(2)O , E^(@) = 1.51V MnO_(2) + 4H^(+) + 2e^(-) righarrow Mn^(2+) + 2H_(2)O E^(@) = 1.23V E_(MnO_(4)^(-)|MnO_(2)

E^(@) for Cl_2 (g) +2e^(-)to2Cl^- (aq) is 1.36 V, E^(@) for Cl^- (aq) to1//2cl_2 (g) +e^- is:

FIITJEE-CHEMICAL ENERGETICS -ASSIGNMENT PROBLEMS (SECTION (II) JEE ADVANCED WITH SINGLE CORRECT CHOICE)
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