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Given that at 25^(@) C [Ag(NH(3))(2)]^...

Given that at `25^(@)` C
`[Ag(NH_(3))_(2)]^(+) + e^(-) to Ag_(s) + 2NH_(3) , E^(@) = 0.02` V
and `Ag^(+) + 1e^(-) to Ag(s) , E^(@) = 0.8 V`
Hence the order of magnitude of equilibrium constant of the reaction.
`[Ag(NH_(3))_(2)] to Ag^(+) + 2NH_(3)` will be (antilog 0.22 = 1.66)

A

`10^(-10)`

B

`10^(-6)`

C

`10^(-14)`

D

`10^(-18)`

Text Solution

Verified by Experts

The correct Answer is:
C
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