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Ionisation energy of Al=5137 kJ "mole"^(...

Ionisation energy of Al=5137 kJ `"mole"^(-1) (DeltaH)` hydration of `Al^(3+) = -4665 kJ "mole"^(-1)`. `(DeltaH)_("hydration")` for `Cl^(-)=-381 kJ "mole"^(-1)`. Which of the following statements is correct?

A

`AlCl_(3)` would remain covalent in aqueous solution

B

Only at infinite dilution `AlCl_(3)` undergoes ionisation.

C

In aqueous solution `AlCl_(3)` becomes ionic.

D

None of these

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The correct Answer is:
C
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Ionisation energy of A1=5137KJmol^(-1)(DeltaH) hydration of Al^(3+)=-4665KJmol^(-1).(DeltaH)_(hydration) for Cl^(-)=-381KJmol^(-1) . Which of the following statement is correct?

Anhydrous AlCl_(3) is covalent. From the date given below, predict whether it would remain covalent or become ionic in aqueous solution. (Ionisation energy for Al is 1537 kJ mol^(-1) ) Delta_("hydration") for Al^(3+) = - 4665 kJ mol^(-1) Delta_("hydration") for Cl^(Ө) = - 381 kJ mol^-1 .

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