Home
Class 12
CHEMISTRY
Lowering of vapour pressure is determine...

Lowering of vapour pressure is determined by Ostward and Walner dynamic method. It is based on the principle, when air is allowed to pass through a solvent or solution, it takes up solvent vapour with it to get itself saturated with vapours at that temperature.
dry ari `to` solution `overset(P_(A)) to underset(A)("solvent") overset(P_(A)^(+)) to "Anhy".CaCl_(2) to` air.
A and B are weighted separately before and after passing dry air. Loss in weight of each set, gives the lowering of vapour pressure. The temperature of air, the solution and the solvent is kept constant.
Dry air was passed through 5 g of solute iini 80 g of water and then through pure water. The loss in weight of solution was 2.5 g and that of pure water was 0.04 g. The molecule weight of solute is:

A

7.143

B

71.43

C

74.3

D

`714.3 g "mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL ENERGETICS

    FIITJEE|Exercise COMPREHENSIONS (COMPREHENSION-VIII)|4 Videos

  • CHEMICAL ENERGETICS

    FIITJEE|Exercise COMPREHENSIONS (COMPREHENSION-IX)|5 Videos

  • CHEMICAL ENERGETICS

    FIITJEE|Exercise COMPREHENSIONS (COMPREHENSION-VI)|5 Videos

  • CARBOXYLIC ACIDS AND ITS DERIVATIVES

    FIITJEE|Exercise SINGLE INTEGER ANSWER TYPE QUESTIONS|1 Videos

  • CHEMICAL EQUILIBRIUM

    FIITJEE|Exercise MATCHING TYPE QUESTIONS|3 Videos

Similar Questions

Explore conceptually related problems

Lowering in vapour pressure is determined by Ostwald and Walker dynamic methed. It is based on the prinicipal , that when air is allowed to pass through a solvent or solution, it takes up solventvapour with it to get itself saturated at that temperature I and II are weighted separately before and after passing dry air. Loss in mass of each set, gives the lowing of vapour pressure. The temperature of air, the solution and the solvent is kept constant. Dry air was passed thorough 9.24 g of solute in 108 g of water and then through pure water. The loss in mass of solution was 3.2 g and that of pure water 0.08 g . The molecular mass (g/mol) of solute is nearly :

Lowering in vapour pressure is determined by Ostwald and Walker dynamic methed. It is based on the prinicipal , that when air is allowed to pass through a solvent or solution, it takes up solventvapour with it to get itself saturated at that temperature I and II are weighted separately before and after passing dry air. Loss in mass of each set, gives the lowing of vapour pressure. The temperature of air, the solution and the solvent is kept constant. Gain in mass of anhydrous CaCl_(2) is proportional to :

Lowering in vapour pressure is determined by Ostwald and Walker dynamic methed. It is based on the prinicipal , that when air is allowed to pass through a solvent or solution, it takes up solventvapour with it to get itself saturated at that temperature I and II are weighted separately before and after passing dry air. Loss in mass of each set, gives the lowing of vapour pressure. The temperature of air, the solution and the solvent is kept constant. Loss in masss of solvent ( w_(II) )will be proportional to :

Lowering in vapour pressure is determined by Ostwald and Walker dynamic methed. It is based on the prinicipal , that when air is allowed to pass through a solvent or solution, it takes up solventvapour with it to get itself saturated at that temperature I and II are weighted separately before and after passing dry air. Loss in mass of each set, gives the lowing of vapour pressure. The temperature of air, the solution and the solvent is kept constant. (P^(@)-P)/(P^(@)) is equal to :

The lowering of vapour pressure of the solvent takes place on dissolving a non-volatile solute because