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0.85% aqueous solution of NaNO(3) is 90%...

0.85% aqueous solution of `NaNO_(3)` is 90% dissociated at `27^(@)` C. Calculate its osmotic pressure. `(R= 0.082 L atm K^(-1) "mol"^(-1))[d = 1 g cm^(-3)]`

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The correct Answer is:
`-5` atm
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