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What is the molality of solution consist...

What is the molality of solution consisting of 33.0 mL of benzene `(C_(6)H_(6),d=0.877 g mL^(-1))` in 187 mL of hexane `(C_(6)H_(14), d= 0.660 g ml^(-1))`?

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The correct Answer is:
3
Mass of Benzene = `33 xx 0.877` g
Mass of benzene `=(28.941)/78 = 0.371`
Mass of hexane `=187 xx 0.66 = 123.42`g
`m=(0.371 xx 1000)/(123.42) = 3.006`
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