Home
Class 12
CHEMISTRY
What are the product obtained when buten...

What are the product obtained when butene undergoes addition reaction of HBr in different conditions.
(i) In absence of peroxide
(ii) In presence of peroxide

Text Solution

Verified by Experts

`underset("2-Bromobutane")(CH_(3)-underset(Br)underset(|)CH-CH_(2)-CH_(3)) underset("No peroxide")overset((i))larr CH_(2)=CH-CH_(3) underset("Peroxide")overset((ii))to underset("1-Bromobutane")(Br-CH_(2)-CH_(2)-CH_(2)-CH_(3))`
(i) 2-Bromobutane
(ii) Bromobutane
Promotional Banner

Similar Questions

Explore conceptually related problems

Write IUPAC names of the products obtained by addition reactions of HBr to hex-1-ene (i) in the absence of peroxide and (ii) in the presence of peroxide.

How will propene react with HBr (i) in the presence of peroxide (ii) in the absence of any peroxide ?

The major product obtained by the addition reaction of HBr to 4-methylpent-1-ene in the presence of peroxide is:

Reaction of HBr with propene in the presence of peroxide gives :-

Reaction of HBr with propene in absence of peroxide is a/an:

Find the products obtained by the addition of HBr "to hex -1-ene " (i) in the presence of preoxide (ii) in the absence of peroxide Also write their IUPAC names. (i) Strategy: In the presence of peroxides, the particle that attacks the double bond first is the large bromine atom. It attaches itself to the less hindered carbon atom to form a more stable free radical. The result is anti-Markovnikov's addition. (ii) Strategy: In the absence of peroxides, the particle that attacks the double bond first is a proton ( beacuse a proton is small, steric effect are not important). It attaches itself to a carbon atom by an ionic mechanism to form the most stable carbocation. The result is Markovnikov's addition.