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Natural rubber is a polymer of isoprene(...

Natural rubber is a polymer of isoprene(2-methylbuta-1, 3-diene). If natural rubbber is treated with `O_(3)` followed by Zn/`H_(2)O`, the final product will be

A

B

`CH_3-overset(O)overset(||)C-CH_2-CH_2-CHO`

C

`CH_3-CH_2-overset(O)overset(||)C-CH_2-CHO`

D

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to follow these steps: ### Step 1: Understand the structure of isoprene Isoprene, or 2-methylbuta-1,3-diene, has the following structure: ``` CH2=C(CH3)-C=CH2 ``` This structure consists of a five-carbon chain with two double bonds and a methyl group on the second carbon. ### Step 2: Polymerization of isoprene Natural rubber is a polymer made up of many isoprene units. The polymerization of isoprene involves the addition of multiple isoprene monomers to form long chains. ### Step 3: Ozonolysis of natural rubber When natural rubber (a polymer of isoprene) is treated with ozone (O3), it undergoes ozonolysis. This reaction cleaves the double bonds in the polymer, resulting in the formation of carbonyl compounds. ### Step 4: Reduction of ozonolysis products After ozonolysis, the product is treated with zinc (Zn) and water (H2O), which reduces the ozonolysis products. The ozonolysis of isoprene results in the formation of two types of carbonyl compounds: aldehydes and ketones. ### Step 5: Identify the final products The ozonolysis of isoprene will yield: - Acetone (CH3COCH3) - Formaldehyde (HCHO) However, since we are dealing with the polymer of isoprene, the final products after ozonolysis and reduction will be: - Acetaldehyde (CH3CHO) - Formaldehyde (HCHO) Thus, the final products will be: - One molecule of acetaldehyde (CH3CHO) - One molecule of formaldehyde (HCHO) ### Final Answer The final products after treating natural rubber with O3 followed by Zn/H2O will be: - Acetaldehyde (CH3CHO) and Formaldehyde (HCHO) ---
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