A : Propene reacts with HBr in presence of `H_(2)O_(2)` gives 2-bromopropane as a major product.
R : This reaction proceeds always through `2^(@)` free radical as intermediate.

Options

A. If both Assertion & Reason are true and the reason is the correct explanation of the assertion, then mark (1).
B. If both Assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark (2)
C. if Assertion is true statement but Reason is false, then mark (3)
D. If both Assertion and Reason are false statements, then mark (4)

Answer

To analyze the given statements about the reaction of propene with HBr in the presence of H2O2, let's break down the assertion (A) and reason (R) step by step.

### Step-by-Step Solution:

1. **Understanding the Reaction**:
- Propene (C3H6) reacts with HBr (hydrobromic acid) in the presence of H2O2 (hydrogen peroxide).
- In the absence of H2O2, the reaction follows Markovnikov's rule, leading to the formation of 2-bromopropane as the major product.

2. **Role of H2O2**:
- When H2O2 is present, it initiates a free radical mechanism.
- This mechanism leads to anti-Markovnikov addition, resulting in the formation of 1-bromopropane as the major product instead of 2-bromopropane.

3. **Assertion Analysis (A)**:
- The assertion states that propene reacts with HBr in the presence of H2O2 to give 2-bromopropane as the major product.
- This statement is **false** because the presence of H2O2 leads to the formation of 1-bromopropane as the major product.

4. **Reason Analysis (R)**:
- The reason states that this reaction proceeds always through a 2° (secondary) free radical as an intermediate.
- This statement is also **false** because, in the presence of H2O2, the reaction actually proceeds through a 1° (primary) free radical intermediate.

5. **Conclusion**:
- Both the assertion and the reason are false.
- Therefore, the correct answer is that both statements are incorrect.

### Final Answer:
- Assertion (A) is false.
- Reason (R) is false.