Identify the final product `CH_(2) = CH_(2) overset (Cl_(2)//H_(2)O)to X overset(-aq.KOH) to Y`

Options

A. 2-chloroethanol
B. 2-chloromethanol
C. 1-chloroethanol
D. Ethylene giycol

Answer

To identify the final product of the given reaction sequence, we will follow the steps outlined in the video transcript.

### Step 1: Reaction of Ethylene with Chlorine
The starting compound is ethylene (CH₂=CH₂). When ethylene reacts with chlorine (Cl₂), it undergoes an electrophilic addition reaction. The double bond in ethylene acts as a nucleophile and attacks one of the chlorine atoms, leading to the formation of a chlorinated product.

**Reaction:**
\[ \text{CH}_2= \text{CH}_2 + \text{Cl}_2 \rightarrow \text{CH}_2\text{Cl}-\text{CH}_2\text{Cl} \]

**Product X:**
The product formed from this reaction is 1,2-dichloroethane (X).

### Step 2: Reaction of X with Water
Next, the product X (1,2-dichloroethane) reacts with water (H₂O). In this step, one of the chlorine atoms is replaced by a hydroxyl group (OH) through a nucleophilic substitution reaction.

**Reaction:**
\[ \text{CH}_2\text{Cl}-\text{CH}_2\text{Cl} + \text{H}_2\text{O} \rightarrow \text{CH}_2\text{OH}-\text{CH}_2\text{Cl} + \text{HCl} \]

**Product Y:**
The product formed here is 2-chloroethanol (Y).

### Step 3: Reaction of Y with Aqueous KOH
Finally, the product Y (2-chloroethanol) reacts with aqueous potassium hydroxide (KOH). In this reaction, the chlorine atom is replaced by a hydroxyl group (OH) through another nucleophilic substitution reaction.

**Reaction:**
\[ \text{CH}_2\text{OH}-\text{CH}_2\text{Cl} + \text{KOH} \rightarrow \text{CH}_2\text{OH}-\text{CH}_2\text{OH} + \text{KCl} \]

**Final Product:**
The final product is ethylene glycol (Y), which is 1,2-ethanediol.

### Summary of Products:
- **Product X:** 1,2-dichloroethane
- **Product Y:** Ethylene glycol (1,2-ethanediol)

### Final Answer:
The final product Y is ethylene glycol.

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