Which one of the following compounds would not be easily oxidised by `K_(2) Cr_(2) O_(7) "in dil" H_(2) SO_(4)` ?

Options

A. `CH_(3) OH`
B. `(CH_(3))_(3)COH`
C. `CH_(3)CH_(2)OH`
D. `CH_(3)CHO`

Answer

To determine which compound would not be easily oxidized by \( K_2Cr_2O_7 \) in dilute \( H_2SO_4 \), we need to analyze the oxidation potential of the given compounds, particularly focusing on the presence of hydrogen atoms on the alpha carbon of alcohols.

### Step-by-Step Solution:

1. **Identify the Compounds**:
We need to look at the four compounds provided in the question. Typically, these compounds will include different types of alcohols, aldehydes, or ketones.

2. **Understand Oxidation of Alcohols**:
Alcohols can be oxidized to aldehydes, ketones, or carboxylic acids depending on the structure of the alcohol. Primary alcohols can be oxidized to aldehydes and then to carboxylic acids. Secondary alcohols can be oxidized to ketones. Tertiary alcohols, however, do not have a hydrogen atom on the carbon that is bonded to the hydroxyl group, making them resistant to oxidation.

3. **Analyze Each Compound**:
- **Primary Alcohol**: Can be oxidized to an aldehyde and then to a carboxylic acid.
- **Secondary Alcohol**: Can be oxidized to a ketone.
- **Tertiary Alcohol**: Cannot be oxidized easily because there is no hydrogen atom on the alpha carbon to be replaced during oxidation.
- **Aldehyde**: Can be oxidized to a carboxylic acid.

4. **Determine the Compound that Cannot be Oxidized**:
Among the compounds, the tertiary alcohol is the one that cannot be easily oxidized by \( K_2Cr_2O_7 \) in dilute \( H_2SO_4 \) because it lacks a replaceable hydrogen atom on the alpha carbon.

5. **Conclusion**:
Therefore, the compound that would not be easily oxidized is the tertiary alcohol.

### Final Answer:
The compound that would not be easily oxidized by \( K_2Cr_2O_7 \) in dilute \( H_2SO_4 \) is the tertiary alcohol.