`CH_(3) CH_(2) +cl+Ag_(2)O overset(Delta)to ` Product . Product formed in the reaction is

Options

A. `CH_(3) CH_(2) - O - CH_(2) CH_(3)`
B. `CH_(3) CH_(2) Cl + AgCl`
C. `CH_(3) CH_(2) - OH + AgCl`
D. `(CH_(3) CH_(2) - O)_(2) Ag`

Answer

To solve the question, we need to analyze the reaction between the alkyl halide \( CH_3CH_2Cl \) and \( Ag_2O \) when heated. Here’s the step-by-step breakdown of the reaction:

### Step 1: Identify the Reactants
We have the alkyl halide \( CH_3CH_2Cl \) (ethyl chloride) and silver oxide \( Ag_2O \).

**Hint:** Look for the functional groups in the reactants that will participate in the reaction.

### Step 2: Understand the Role of \( Ag_2O \)
Silver oxide \( Ag_2O \) acts as a source of hydroxide ions and can facilitate the nucleophilic substitution reaction by providing oxygen with lone pairs that can attack the carbon atom bonded to chlorine.

**Hint:** Consider how \( Ag_2O \) can interact with the alkyl halide.

### Step 3: Mechanism of the Reaction
When heated, the chlorine atom in \( CH_3CH_2Cl \) is polarized due to the electronegativity difference between carbon and chlorine. The oxygen from \( Ag_2O \) will attack the carbon atom, leading to the displacement of the chlorine atom.

**Hint:** Think about how nucleophiles attack electrophiles in organic reactions.

### Step 4: Formation of Products
The chlorine atom leaves as chloride ion \( Cl^- \), and a bond is formed between the carbon and the oxygen from \( Ag_2O \). This results in the formation of an ether.

The reaction can be summarized as follows:
\[ CH_3CH_2Cl + Ag_2O \xrightarrow{\Delta} CH_3CH_2OAg + AgCl \]

**Hint:** Identify the products formed after the reaction and how they are structured.

### Step 5: Final Product
The final product of the reaction is ethyl ether \( CH_3CH_2OCH_3 \) (diethyl ether), along with silver chloride \( AgCl \) as a byproduct.

**Hint:** Ensure you understand the structure of the ether formed and the byproducts.

### Conclusion
The product formed in the reaction of \( CH_3CH_2Cl \) with \( Ag_2O \) upon heating is diethyl ether \( CH_3CH_2OCH_3 \).

**Final Answer:** The product formed in the reaction is \( CH_3CH_2OCH_3 \) (diethyl ether).