`CH_(3)underset(CH_(3))underset(|)(CH)-CH=CH_(2)underset((ii)H_(2)O_(2)//OH)overset((i)B_(2)H_(4))toXunderset(140^(@))overset(H_(2)SO_(4))toY`
What is Y ?

Options

A. `CH_(3) -underset(CH_(3))underset(|)(CH)-CH_(2)-CH_(2)-O-CH_(2)-CH_(2)-underset(CH_(3))underset(|)(CH)-CH_(3)`
B. `CH_(3) -underset(CH_(3))underset(|)(CH)-CH=CH_(2)`
C. `CH_(3)-underset(CH_(3))underset(|)(CH)-underset(CH_(3))underset(|)(CH)-O-underset(CH_(3))underset(|)(CH)-underset(CH_(3))underset(|)(CH)-CH_(3)`
D. `CH_(3)-underset(C_(2)H_(5))underset(|)overset(CH_(3))overset(|)(C)-O-underset(C_(2)H_(5))underset(|)overset(CH_(3))overset(|)(C)-CH_(3)`

Answer

To solve the given problem, let's break down the steps involved in the reaction sequence:

### Step 1: Identify the Starting Compound
The starting compound is an alkene:
\[ CH_3CH(CH_3)CH=CH_2 \]

### Step 2: Reaction with B2H6
The first reaction involves the addition of diborane (B2H6) to the alkene. According to the anti-Markovnikov rule, the boron atom will attach to the less substituted carbon atom of the alkene, resulting in the formation of a trialkyl borane.

The product after this step (let's call it X) will be:
\[ CH_3CH(CH_3)CH_2B(OH)_2 \]

### Step 3: Oxidation with H2O2 and OH-
Next, we treat the trialkyl borane with hydrogen peroxide (H2O2) in the presence of hydroxide ions (OH-). This will lead to the oxidation of the boron compound to form an alcohol.

The resulting alcohol (X) will be:
\[ CH_3CH(CH_3)CH_2OH \]

### Step 4: Reaction with Concentrated H2SO4
Now, we will react the alcohol (X) with concentrated sulfuric acid (H2SO4) at a temperature of 140°C. This reaction will favor elimination due to the high temperature, leading to the formation of an ether.

### Step 5: Formation of Ether (Y)
The elimination reaction will result in the formation of an ether. The structure of the ether (Y) will be:
\[ CH_3CH(CH_3)CH_2OCH_2CH_2CH(CH_3) \]

### Final Answer
Thus, the final product Y is:
\[ CH_3CH(CH_3)CH_2OCH_2CH_2CH(CH_3) \]