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A : When 3,3-dimethyl butan - 2 - ol is ...

A : When 3,3-dimethyl butan - 2 - ol is heated in presence of concentrated `H_(2)SO_(4)` then 2, 3-dimethyl but -2-ene is formed as major product .
R : In this reaction , carbocation is formed as an intermediate

A

If both Assertion & Reason are true and the reason is the correct explanation of the assertion, then mark (1)

B

If both Assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark (2)

C

If Assertion is true statement but Reason is false , then mark (3)

D

If both Assertion and Reason are false statements , then mark (4)

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AI Generated Solution

The correct Answer is:
To solve the assertion-reason question regarding the reaction of 3,3-dimethylbutan-2-ol with concentrated H₂SO₄, we will analyze both the assertion (A) and the reason (R) step by step. ### Step 1: Understanding the Assertion (A) The assertion states that when 3,3-dimethylbutan-2-ol is heated in the presence of concentrated H₂SO₄, 2,3-dimethylbut-2-ene is formed as the major product. - **Structure of 3,3-dimethylbutan-2-ol**: - The compound has four carbon atoms (butane) with a hydroxyl (OH) group on the second carbon and two methyl (CH₃) groups on the third carbon. - **Heating with H₂SO₄**: - Concentrated sulfuric acid acts as a dehydrating agent, facilitating the elimination of water (H₂O) and leading to the formation of an alkene. ### Step 2: Reaction Mechanism 1. **Protonation of the Alcohol**: - The hydroxyl group (OH) of 3,3-dimethylbutan-2-ol gets protonated by H₂SO₄, converting it into a better leaving group (water). 2. **Formation of Carbocation**: - The protonation leads to the loss of water, resulting in the formation of a carbocation. In this case, a secondary carbocation is formed initially. 3. **Carbocation Rearrangement**: - The secondary carbocation can undergo rearrangement to form a more stable tertiary carbocation by a methyl shift from the adjacent carbon. 4. **Elimination to Form Alkene**: - The final step involves the elimination of a proton (H⁺) from a neighboring carbon, leading to the formation of a double bond (alkene). ### Step 3: Identifying the Major Product - The major product formed is 2,3-dimethylbut-2-ene, which is more stable due to the presence of more alkyl groups around the double bond (according to Zaitsev's rule). ### Step 4: Understanding the Reason (R) The reason states that in this reaction, a carbocation is formed as an intermediate. - **Correctness of the Reason**: - This statement is true, as the formation of a carbocation is a crucial step in the dehydration mechanism of alcohols. ### Conclusion - Both the assertion (A) and the reason (R) are true. - The reason (R) correctly explains the assertion (A) because the formation of a carbocation is essential for the elimination reaction leading to the alkene product. ### Final Answer - **Assertion (A)**: True - **Reason (R)**: True - **Explanation**: R is the correct explanation of A.
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