An amine reacts with `CH_(3)SO_(2)Cl` and the product is soluble in alkali, amine is

Options

A. `1^(@)` amine
B. `2^(@)` amine
C. `3^(@)` amine
D. All of these

Answer

To solve the problem, we need to identify the type of amine that reacts with methyl sulfonyl chloride (CH₃SO₂Cl) and produces a product that is soluble in alkali. We can analyze the reactions of different types of amines with this reagent.

### Step-by-Step Solution:

1. **Understanding the Reaction**:
Methyl sulfonyl chloride (CH₃SO₂Cl) is a sulfonyl chloride that can react with amines. The reaction is known as the Hinsberg reaction, which is used to differentiate between primary, secondary, and tertiary amines.

2. **Reactions with Different Amines**:
- **Primary Amine**: When a primary amine reacts with CH₃SO₂Cl, it forms a sulfonamide and releases HCl. The resulting sulfonamide has an acidic hydrogen, making it soluble in alkali.
- **Secondary Amine**: A secondary amine will also react with CH₃SO₂Cl, but the product formed does not have an acidic hydrogen. Therefore, it is insoluble in alkali.
- **Tertiary Amine**: Tertiary amines do not react with sulfonyl chlorides because they lack a hydrogen atom on the nitrogen to form HCl. Thus, no product is formed.

3. **Conclusion**:
Since the product formed from the reaction must be soluble in alkali, the only type of amine that fits this criterion is a primary amine. Therefore, the amine in question is a primary amine.

### Final Answer:
The amine is a primary amine.

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