The cylinder of propane gas at `25^(@)C` exerted a pressure of 10 atmosphere. When exposed to sunlight it warmed upto `45^(@)C.` What pressure does the container now experience?

Explanation

To solve the problem, we will use the relationship between pressure and temperature of a gas at constant volume, which is given by Gay-Lussac's Law. The formula we will use is:

\[ \frac{P_1}{T_1} = \frac{P_2}{T_2} \]

Where:
- \( P_1 \) = initial pressure
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