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30cm^(3) of a gas at 2.02 atm and 25^(@)...

`30cm^(3)` of a gas at 2.02 atm and `25^(@)C` was compressed to `15cm^(3)" at "35^(@)C.` Calculate the final pressure of the gas.

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To solve the problem of finding the final pressure of the gas after it has been compressed, we will use the combined gas law, which is given by the formula: \[ \frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2} \] ### Step 1: Identify the given values From the question, we have the following values: ...
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AAKASH INSTITUTE-STATES OF MATTER-ASSIGNMENT (SECTION-D)
  1. 30cm^(3) of a gas at 2.02 atm and 25^(@)C was compressed to 15cm^(3)" ...

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  2. A : The value of van der Waal's constant 'a' of Cl(2) is larger than t...

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  3. A : On increasing the temperature , the hight of the peak of the Maxwe...

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  4. A: A real gas will approach ideal behaviour at high temperature and lo...

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  5. A. Rate of diffusion of H2 is 1.44 times of He. R: Under similar con...

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  6. Assertion: At constant temperature, if pressure on the gas is doubled,...

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  7. A: For a certain amount of gas, PV is always constant at constant temp...

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  8. Assertion : The pressure of real gas is less than the pressure of idea...

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  9. A: Helium shows only positive deviation from ideal behaviour. R : He...

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  10. A: Hot air balloon rises up by displacing the denser air of the atmosp...

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  11. A: H(2) when allowed to expand at room temperature it causes heating e...

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  12. A: At very high pressures, compressibility factor is greater than 1. ...

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  13. A : Greater is the ciritical temperature, more difficult is to liquefy...

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  14. A: For a real gas if molar volume is less than 22.4 V litres, at S.T.P...

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  15. A :Vapour pressure of the liquid increases with increase in temperatur...

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  16. A : At constant temperature, thegas density is directly proportional t...

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