The volumes of ozone and chlorine diffusing in the same time are `35 mL` and `29mL`, respectively. If the molecular weight of chlorine is `71`, calculate the molecular weight of ozone.

Explanation

`(r(O_3))/(r(Cl_2))=sqrt ((M(Cl_2))/(M(O_3))`
Rate of diffusion in sam time is proportional to volume diffuese so
`(V(O_3))/(V(Cl_2))=sqrt((M(Cl_2))/(M(O_3)))`
`35/29= sqrt((71)/(M(O_3)))rArr (35)^2/(29)^2=71/(M(O_3)) rArr M(O_3)=48.74 `