A fluoride of phosphorous in gaseous state was found to diffuse 2.12 times more slowly than nitrogen under similar conditions. Calculate the molecular mass and molecular formula of this fluoride which contains one atom of phosphorous per molecule.

Explanation

To solve the problem step by step, we will use Graham's law of diffusion and the information provided in the question.

### Step 1: Understand the Given Information
We know that a fluoride of phosphorus diffuses 2.12 times more slowly than nitrogen. This means that the rate of diffusion of the phosphorus fluoride (let's denote it as gas X) is less than that of nitrogen.

### Step 2: Use Graham's Law of Diffusion
Graham's law states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass. Mathematically, this can be expressed as:

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