Rate of diffusion of gas A is `(1)/(2)` that of gas 'B'. If molecular mass of gas A is 16 than calculate molecular mass of gas 'B'.

Explanation

To solve the problem, we will use Graham's law of diffusion, which states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass.

### Step-by-Step Solution:

1. **Understand the Given Information**:
- Rate of diffusion of gas A (R_A) is \( \frac{1}{2} \) that of gas B (R_B).
- Molecular mass of gas A (M_A) = 16 g/mol.
- We need to find the molecular mass of gas B (M_B).
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