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At critical temperature pressure and vol...

At critical temperature pressure and volume. The compressibility factor (Z) is-

A

`(8)/(3)`

B

`(5)/(3)`

C

`(3)/(5)`

D

`(3)/(8)`

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The correct Answer is:
To find the compressibility factor (Z) at critical temperature, pressure, and volume, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Compressibility Factor (Z)**: The compressibility factor (Z) is defined as: \[ Z = \frac{P V}{R T} \] where \(P\) is the pressure, \(V\) is the volume, \(R\) is the universal gas constant, and \(T\) is the temperature. 2. **Using Critical Parameters**: At critical conditions, we can express Z in terms of critical pressure (\(P_c\)), critical volume (\(V_c\)), and critical temperature (\(T_c\)): \[ Z = \frac{P_c V_c}{R T_c} \] 3. **Substituting Critical Values**: We know the following relationships for critical parameters: - \(T_c = \frac{8a}{27bR}\) - \(V_c = 3b\) - \(P_c = \frac{a}{27b^2}\) Substituting these into the equation for Z: \[ Z = \frac{P_c V_c}{R T_c} = \frac{\left(\frac{a}{27b^2}\right) \left(3b\right)}{R \left(\frac{8a}{27bR}\right)} \] 4. **Simplifying the Expression**: Now we simplify the expression step by step: - Substitute \(P_c\) and \(V_c\): \[ Z = \frac{\frac{a \cdot 3b}{27b^2}}{R \cdot \frac{8a}{27bR}} \] - This simplifies to: \[ Z = \frac{3a}{27b} \cdot \frac{27bR}{8a} \] - Canceling out common terms: \[ Z = \frac{3}{8} \] 5. **Conclusion**: Thus, the compressibility factor (Z) at critical temperature, pressure, and volume is: \[ Z = \frac{3}{8} \] ### Final Answer: The compressibility factor (Z) at critical temperature, pressure, and volume is \( \frac{3}{8} \). ---
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