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Ratio of C(p) and C(v) of a gas X is 1.4...

Ratio of `C_(p)` and `C_(v)` of a gas X is 1.4, the number of atom of the gas 'X' present in 11.2 litres of it at NTP will be

A

`6.02xx 10^23`

B

`1.2 xx 10^(23)`

C

`3.01 xx 10^(23)`

D

`12.04 xx 10^(23)`

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