0.4 g of Organic Compound gave 0.188 g of AgBr. The percentage of Br in the compound is

Options

A. 39.8
B. `46.0`
C. `20.0`
D. `40.0`

Explanation

To find the percentage of bromine (Br) in the organic compound using the data provided, we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Data:**
- Weight of organic compound = 0.4 g
- Weight of AgBr formed = 0.188 g
- Atomic weight of bromine (Br) = 80 g/mol
- Atomic weight of silver (Ag) = 108 g/mol

2. **Use the Formula for Percentage of Halogen:**
The formula for calculating the percentage of halogen (in this case, bromine) in the organic compound is:
\[ \text{Percentage of Br} = \frac{\text{Atomic weight of Br}}{\text{Atomic weight of Br} + \text{Atomic weight of Ag}} \times \frac{\text{Weight of AgBr}}{\text{Weight of organic compound}} \times 100 \]

3. **Substitute the Values into the Formula:**
- Atomic weight of Br = 80 g/mol
- Atomic weight of Ag = 108 g/mol
- Weight of AgBr = 0.188 g
- Weight of organic compound = 0.4 g

Plugging in the values:
\[ \text{Percentage of Br} = \frac{80}{80 + 108} \times \frac{0.188}{0.4} \times 100 \]

4. **Calculate the Denominator:**
\[ 80 + 108 = 188 \]

5. **Calculate the Fraction:**
\[ \frac{80}{188} \approx 0.4255 \]

6. **Calculate the Second Fraction:**
\[ \frac{0.188}{0.4} = 0.47 \]

7. **Combine the Results:**
\[ \text{Percentage of Br} = 0.4255 \times 0.47 \times 100 \]

8. **Final Calculation:**
\[ \text{Percentage of Br} \approx 20\% \]

### Conclusion:
The percentage of bromine in the organic compound is **20%**.

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