The no. of `sigma` & `pi` bonds present in `C_(2)H_(2)` respectively are

Options

A. 1,2
B. 2,1
C. 5,2
D. 3,2

Answer

To determine the number of sigma (σ) and pi (π) bonds in the compound C₂H₂ (ethyne), we can follow these steps:

### Step 1: Understand the Structure of C₂H₂
C₂H₂, also known as ethyne or acetylene, consists of two carbon atoms and two hydrogen atoms. The structural formula can be represented as H-C≡C-H.

### Step 2: Determine the Bonds Between Atoms
- Each carbon atom has four valence electrons and can form four bonds.
- In C₂H₂, the two carbon atoms are connected by a triple bond (C≡C), which consists of one sigma bond and two pi bonds.
- Each carbon atom is also bonded to one hydrogen atom by a single bond (C-H), which is a sigma bond.

### Step 3: Count the Sigma Bonds
- From the triple bond (C≡C), there is **1 sigma bond**.
- From the two C-H bonds, there are **2 sigma bonds** (one from each C-H bond).
- Therefore, the total number of sigma bonds in C₂H₂ is:
- 1 (from C≡C) + 2 (from C-H) = **3 sigma bonds**.

### Step 4: Count the Pi Bonds
- The triple bond (C≡C) consists of **2 pi bonds**.
- There are no additional pi bonds in C₂H₂.
- Therefore, the total number of pi bonds is **2 pi bonds**.

### Final Answer
In C₂H₂, the number of sigma bonds is **3** and the number of pi bonds is **2**.

### Summary
- **Sigma Bonds (σ)**: 3
- **Pi Bonds (π)**: 2

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