Home
Class 11
CHEMISTRY
An organic compound has C and H percenta...

An organic compound has C and H percentage in the ratio 6 : 1 by mass and C and O percentage in the ratio 3 : 4 by mass the compound is

A

HCHO

B

`CH_(3)OH`

C

`CH_(3)CH_(2)OH`

D

`(COOH)_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC PRINCIPLES AND TECHNIQUES

    NARAYNA|Exercise EXERCISE -II-(H.W) (INTRODUCTION, TETRARAVENCE OF CARBON, STRUCTURAL REPRESENTATION OF ORGANIC COMPOUNDS)|6 Videos

  • SOME BASIC PRINCIPLES AND TECHNIQUES

    NARAYNA|Exercise EXERCISE -II-(H.W) (CLASSIFICATION OF ORGANIC COMPOUNDS, IUPAC NOMENCLATURE)|16 Videos

  • SOME BASIC PRINCIPLES AND TECHNIQUES

    NARAYNA|Exercise EXERCISE - II- C.W (QUALITATIVE ANALYSIS OF ORGANIC COMPOUNDS)|2 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    NARAYNA|Exercise EXERCISE - IV|43 Videos

  • STATES OF MATTER

    NARAYNA|Exercise A & R TYPE QUESTIONS|16 Videos

Similar Questions

Explore conceptually related problems

The molecular mass of an organic compound is 78 and its percentage composition is 92.4% C and 7.6% H. Determine the molecular formula of the compound.

In a given compound the elements H, C, O , and N are in the mass ratio 1 : 3 : 4 : 7 The empirical formula of the compound is

An organic compound with C =40 % and H= 6.7% will have the empirical formula

An organic compound with C =40 % and H= 6.7% will have the empirical formula

An organic compound contains C, H , and O . Its elemental analysis gave C(38.71%) and H (9.67%) . The empirical formula of the compound will be

In an organic compound of molar mass greater than 100 containing only C , H and N , the percentage of C is 6 times the percentage of H while the sun of the percentage of C and H is 1.5 times the percentage of N . What is the least molar mass :

An organic compound has the following percentage composition , C = 48 %, H = 8 %, N = 28 % . Calculate the empirical formula of the compound.

An organic compound contains carbon, hydrogen and oxygen. If the ratio percentage of C and H is 6:1 calculate the simplest formula of the compound, given that one molecule of the compound contains half as much oxygen as would be required to burn all the carbon and hydrogen atoms in it to CO_2 and H_2O