A compound with molecular formula `C_(6)H_(14)` has two tertiary carbons. Its IUPAC name is

Options

A. n-hexane
B. 2-methyl pentane
C. 2,3-dimethyl butane
D. 2,3-dimethyl pentane

Answer

To determine the IUPAC name of a compound with the molecular formula \(C_6H_{14}\) that contains two tertiary carbon atoms, we can follow these steps:

### Step 1: Understand Tertiary Carbons
A tertiary carbon is defined as a carbon atom that is bonded to three other carbon atoms. This means we need to identify structures that contain such carbon atoms.

### Step 2: Identify Possible Structures
We will consider various structural isomers of \(C_6H_{14}\) and check for the presence of two tertiary carbons.

1. **n-Hexane**: This is a straight-chain alkane with the structure:
\[ CH_3-CH_2-CH_2-CH_2-CH_2-CH_3 \]
- **Tertiary Carbons**: 0 (none of the carbons are bonded to three other carbons).

2. **2-Methylpentane**: This structure has a five-carbon chain with a methyl group on the second carbon:
\[ CH_3-CH(CH_3)-CH_2-CH_2-CH_3 \]
- **Tertiary Carbons**: 1 (the second carbon is bonded to three carbons).

3. **3-Methylpentane**: This structure has a five-carbon chain with a methyl group on the third carbon:
\[ CH_3-CH_2-CH(CH_3)-CH_2-CH_3 \]
- **Tertiary Carbons**: 1 (the third carbon is bonded to three carbons).

4. **2,2-Dimethylbutane**: This structure has a four-carbon chain with two methyl groups on the second carbon:
\[ CH_3-C(CH_3)_2-CH_2-CH_3 \]
- **Tertiary Carbons**: 1 (the second carbon is bonded to three carbons).

5. **2,3-Dimethylbutane**: This structure has a four-carbon chain with methyl groups on the second and third carbons:
\[ CH_3-CH(CH_3)-CH(CH_3)-CH_3 \]
- **Tertiary Carbons**: 2 (the second and third carbons are both bonded to three carbons).

### Step 3: Confirm the Molecular Formula
Now, we need to ensure that the structure we found has the correct molecular formula \(C_6H_{14}\):
- **2,3-Dimethylbutane** has:
- Total Carbons: \(4\) (from butane) + \(2\) (from two methyl groups) = \(6\)
- Total Hydrogens: \(2 \times 4 + 2 = 14\)

### Step 4: Conclusion
The compound with the molecular formula \(C_6H_{14}\) that has two tertiary carbon atoms is **2,3-dimethylbutane**.

### Final Answer
The IUPAC name of the compound is **2,3-dimethylbutane**.

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