Each mole of Haemoglobin contains four moles of iron. If the percentage of iron in Haemoglobin is 0.35 % by mass. The molar mass of haemoglobin is

Options

A. `6.4 xx 10^(4) gmol^(-1)`
B. `5.6 xx 10^(4) gmol^(-1)`
C. `6.4 xx 10^(5) gmol^(-1)`
D. `5.6 xx 10^(5) gmol^(-1)`

Answer

A

Explanation

No. of iron atoms per molecule = 4
Mass of iron per molecule = `4 xx 56 = 224u`
0.35 parts by mass of iron is present in haemoglobin = 100 parts
224 parts mass of iron is present in haemoglobin
` = (100 xx 224)/(0.35) = 64000`
(or) `6.4 xx 10^(4) gmol^(-1)`