When dry `Cl_(2)` gas is passed over dry salked lime the product obtained is having the structure

Options

A.
B.
C. `Ca(OCl)_(2)`
D. `CaCl_(2)O_(2)`

Answer

To solve the question "When dry Cl₂ gas is passed over dry slaked lime, the product obtained is having the structure?", we will follow these steps:

### Step 1: Understand the Reactants
- **Dry Cl₂ gas**: This is chlorine gas in its dry form.
- **Dry slaked lime**: This is calcium hydroxide (Ca(OH)₂) that has been dried.

### Step 2: Identify the Reaction
When dry Cl₂ gas reacts with dry slaked lime (Ca(OH)₂), the main product formed is bleaching powder, which has the chemical formula Ca(OCl)₂.

### Step 3: Write the Chemical Reaction
The reaction can be represented as:
\[ \text{Ca(OH)}_2 + \text{Cl}_2 \rightarrow \text{Ca(OCl)}_2 + \text{HCl} \]

### Step 4: Identify the Product
The product, bleaching powder, is known as calcium oxychloride (Ca(OCl)₂).

### Step 5: Determine the Structure of the Product
The structure of Ca(OCl)₂ can be broken down as follows:
- Calcium (Ca) has a +2 charge.
- Each OCl (hypochlorite) has a -1 charge.
- Therefore, the overall charge is neutral as +2 from Ca balances with -2 from two OCl groups.

### Step 6: Analyze the Possible Structures
Now, we need to analyze the given options for the structure of bleaching powder:
1. **Option A**: CaOCl₂ - This is the correct formula for bleaching powder.
2. **Option B**: CaCl₂O - This structure is incorrect as it suggests an extra chlorine atom.
3. **Option C**: CaCl₂O₂ - This structure is also incorrect as it suggests an extra chlorine atom.

### Step 7: Conclusion
The correct structure for the product obtained when dry Cl₂ gas is passed over dry slaked lime is represented by the formula Ca(OCl)₂, which corresponds to option A.

### Final Answer
The product obtained is Ca(OCl)₂, which is the structure of bleaching powder.

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