Which one of the following represents the reaction between fluorien and cold dilute NaOH ?

Options

A. `2F_(2)+4NaOH to 4NaF+2H_(2)O`
B. `3F_(2)+NaOH to 5NaF+NaFO_(3)`
C. `F_(2)+2NaOH to NaF+NaOF+H_(2)O`
D. `2F_(2)+2NaOH to 2NaF+OF_(2)+H_(2)O`

Explanation

To determine the reaction between fluorine (F2) and cold dilute sodium hydroxide (NaOH), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in this reaction are fluorine gas (F2) and cold dilute sodium hydroxide (NaOH).

2. **Understand the Reaction Conditions**: The reaction is taking place under cold and dilute conditions. This is important because different conditions can lead to different products.

3. **Write the Initial Reaction**: When fluorine reacts with sodium hydroxide, we can start with the following equation:
\[ F_2 + NaOH \rightarrow ? \]

4. **Determine the Products**: Under cold and dilute conditions, the reaction of fluorine with sodium hydroxide typically produces sodium fluoride (NaF), water (H2O), and oxygen difluoride (OF2). Therefore, the products can be written as:
\[ F_2 + 2 NaOH \rightarrow 2 NaF + H_2O + OF_2 \]

5. **Balance the Reaction**: To balance the equation, we ensure that the number of atoms for each element is the same on both sides:
- On the left, we have 2 fluorine atoms from F2, 2 sodium atoms from 2 NaOH, and 2 oxygen atoms (one from each NaOH).
- On the right, we have 2 sodium atoms from 2 NaF, 2 fluorine atoms from OF2, and 1 oxygen atom from H2O.
Thus, the balanced equation is:
\[ F_2 + 2 NaOH \rightarrow 2 NaF + H_2O + OF_2 \]

6. **Select the Correct Option**: From the given options, we need to identify which one matches this balanced equation. The correct representation of the reaction is the one that includes NaF, H2O, and OF2.

### Conclusion:
The correct representation of the reaction between fluorine and cold dilute sodium hydroxide is:
\[ F_2 + 2 NaOH \rightarrow 2 NaF + H_2O + OF_2 \]