Chlorine reacts with caustic soda (hot) giving NaCl and

Options

A. `NaClO`
B. `NaCIO_(2)`
C. `NaClO_(3)`
D. `NaCIO_(4)`

Answer

To solve the question regarding the reaction of chlorine with caustic soda (sodium hydroxide) to produce sodium chloride (NaCl) and another product, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants and Products**:
- The reactants are chlorine gas (Cl₂) and caustic soda (NaOH).
- The products include sodium chloride (NaCl) and another compound, which we need to determine.

2. **Write the Unbalanced Chemical Equation**:
- The unbalanced reaction can be written as:
\[ \text{Cl}_2 + \text{NaOH} \rightarrow \text{NaCl} + \text{?} \]

3. **Determine the Other Product**:
- When chlorine reacts with sodium hydroxide (especially in hot conditions), one of the products formed is sodium chlorate (NaClO₃) along with sodium chloride (NaCl).
- Thus, the products are NaCl and NaClO₃.

4. **Write the Balanced Chemical Equation**:
- The balanced equation for the reaction is:
\[ 3\text{Cl}_2 + 6\text{NaOH} \rightarrow 5\text{NaCl} + \text{NaClO}_3 + 3\text{H}_2\text{O} \]
- Here, we have balanced the number of atoms for each element on both sides of the equation.

5. **Confirm the Balancing**:
- Count the number of each type of atom on both sides:
- Chlorine (Cl): 6 on the left (from 3 Cl₂) and 6 on the right (5 from NaCl and 1 from NaClO₃).
- Sodium (Na): 6 on the left (from 6 NaOH) and 6 on the right (5 from NaCl and 1 from NaClO₃).
- Oxygen (O): 6 on the left (from 6 NaOH) and 6 on the right (3 from NaClO₃ and 3 from 3 H₂O).
- Hydrogen (H): 6 on the left (from 6 NaOH) and 6 on the right (from 3 H₂O).
- Since all atoms are balanced, the equation is correct.

### Final Answer:
The reaction of chlorine with caustic soda (hot) produces sodium chloride (NaCl) and sodium chlorate (NaClO₃).

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