Oxidation states of chlorine in the products when chlorine react with cold and dil. NaOH are

Options

A. `0,-1`
B. `-1,+1`
C. `-1,+3`
D. `-1,+5`

Explanation

To determine the oxidation states of chlorine in the products formed when chlorine reacts with cold and dilute NaOH, we will analyze the compounds produced in this reaction: sodium chloride (NaCl) and sodium hypochlorite (NaOCl).

### Step-by-Step Solution:

1. **Identify the Products**: When chlorine (Cl₂) reacts with cold and dilute sodium hydroxide (NaOH), the products formed are sodium chloride (NaCl) and sodium hypochlorite (NaOCl).

2. **Determine the Oxidation State in NaCl**:
- The formula for sodium chloride is NaCl.
- Sodium (Na) is an alkali metal and has a common oxidation state of +1.
- Let the oxidation state of chlorine (Cl) in NaCl be \( x \).
- The overall charge of NaCl is 0 (as it is a neutral compound).
- Set up the equation:
\[ +1 + x = 0 \]
- Solving for \( x \):
\[ x = -1 \]
- Therefore, the oxidation state of chlorine in NaCl is **-1**.

3. **Determine the Oxidation State in NaOCl**:
- The formula for sodium hypochlorite is NaOCl.
- Sodium (Na) again has an oxidation state of +1.
- Oxygen (O) typically has an oxidation state of -2.
- Let the oxidation state of chlorine (Cl) in NaOCl be \( y \).
- The overall charge of NaOCl is also 0.
- Set up the equation:
\[ +1 - 2 + y = 0 \]
- Solving for \( y \):
\[ y = +1 \]
- Therefore, the oxidation state of chlorine in NaOCl is **+1**.

4. **Summarize the Findings**:
- The oxidation states of chlorine in the products when chlorine reacts with cold and dilute NaOH are:
- In NaCl: **-1**
- In NaOCl: **+1**

5. **Conclusion**:
- The oxidation states of chlorine in the products are **-1 and +1**.