In Moissan's method Fluorine was prepared by the electrolysis of

Options

A. Fused HF
B. Molten KF
C. HF dissolved in Molten KF
D. `OF_(2)`

Explanation

To solve the question regarding the preparation of Fluorine using Moissan's method, we can break down the process step by step:

### Step-by-Step Solution:

1. **Understanding Moissan's Method**:
- Moissan's method is a technique used for the preparation of Fluorine gas. It involves the electrolysis process.

2. **Identifying the Electrolyte**:
- In this method, the electrolyte used is Hydrofluoric acid (HF) dissolved in molten Potassium Fluoride (KF). This combination is crucial for the electrolysis to occur effectively.

3. **Dissociation of Electrolyte**:
- When HF is dissolved in molten KF, it dissociates into ions. The dissociation can be represented as:
- HF → H⁺ + F⁻
- KF → K⁺ + F⁻
- Therefore, the ions present in the solution are H⁺, K⁺, and F⁻.

4. **Movement of Ions**:
- During electrolysis, the negatively charged F⁻ ions will migrate towards the anode (positive electrode) because opposite charges attract.

5. **Oxidation at the Anode**:
- At the anode, oxidation occurs. The F⁻ ions lose electrons (oxidation) to form Fluorine gas (F₂). The reaction can be summarized as:
- 2F⁻ → F₂ + 2e⁻
- This indicates that two fluoride ions combine to form one molecule of Fluorine gas.

6. **Electrodes Used**:
- The electrodes used in this electrolysis process are typically made of Platinum and Iridium due to their high resistance to corrosion and ability to conduct electricity efficiently.

7. **Conclusion**:
- Therefore, the correct answer to the question is that Fluorine is prepared by the electrolysis of Hydrofluoric acid (HF) dissolved in molten Potassium Fluoride (KF).

### Final Answer:
Fluorine was prepared by the electrolysis of HF dissolved in molten KF.

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