Iodine can be obtained from NaI solution by the action of

Options

A. Chlorine
B. bromine
C. soluable chloride
D. soluble bromine

Explanation

To obtain iodine (I2) from a sodium iodide (NaI) solution, we can use chlorine (Cl2) or bromine (Br2) as oxidizing agents. Here’s a step-by-step breakdown of the process:

### Step 1: Understand the Reaction
We need to oxidize iodide ions (I-) from NaI to iodine (I2). Chlorine (Cl2) and bromine (Br2) are both stronger oxidizing agents than iodine, which means they can oxidize iodide ions to iodine.

### Step 2: Write the Reaction with Chlorine
When chlorine gas (Cl2) is bubbled through a sodium iodide solution, the reaction can be written as:
\[ 2 \text{NaI} + \text{Cl}_2 \rightarrow \text{I}_2 + 2 \text{NaCl} \]
In this reaction, the iodide ions (I-) are oxidized to iodine (I2), while chlorine is reduced to chloride ions (Cl-).

### Step 3: Write the Reaction with Bromine
Similarly, when bromine gas (Br2) is used, the reaction is:
\[ 2 \text{NaI} + \text{Br}_2 \rightarrow \text{I}_2 + 2 \text{NaBr} \]
Again, iodide ions are oxidized to iodine (I2), while bromine is reduced to bromide ions (Br-).

### Step 4: Identify the Correct Options
From the above reactions, we can conclude that iodine can be obtained from a NaI solution by the action of either chlorine or bromine. Therefore, the correct answers are:
- Chlorine (Cl2)
- Bromine (Br2)

### Step 5: Exclude Soluble Chlorides and Bromides
The question also mentions soluble chlorides and bromides. However, these do not act as oxidizing agents in the same way that Cl2 and Br2 do. Therefore, we can exclude those options.

### Final Conclusion
Iodine can be obtained from a sodium iodide solution by the action of chlorine (Cl2) or bromine (Br2).

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