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Match the following {:(,"List-I",,"Lis...

Match the following
`{:(,"List-I",,"List-II"),((A),ClF,(1),sp^(3)d),((B),ClF_(3),(2),"T-shape"),((C),ClF_(5),(3),"linear"),(,,(4),sp^(3)d^(2)),(,,(5),"no. of lone pairs one"),(,,(6),"pentagonal Bi-pyramidal"):}`
The correct match is

A

A-3 ,B-1,2 C-4,5

B

A-3 B-1,2 C-5, 6

C

A-3 B-1,6 C-4, 5

D

A-3 B-3,4 C-5,6

Text Solution

AI Generated Solution

The correct Answer is:
To solve the matching question, we need to analyze the compounds listed in List-I (ClF, ClF3, ClF5) and determine their hybridization, shape, and number of lone pairs. We will then match these properties with the corresponding options in List-II. ### Step-by-Step Solution: 1. **Analyze ClF (Chlorine Monofluoride)**: - Chlorine (Cl) has 7 valence electrons. - In ClF, chlorine forms one bond with fluorine, using 1 of its 7 electrons. - This leaves 6 electrons, which can be arranged as 3 lone pairs. - **Hybridization**: The hybridization is determined by the number of bonding pairs and lone pairs. Here, we have 1 bond and 3 lone pairs, which gives us a total of 4 regions of electron density. This corresponds to **sp³ hybridization**. - **Shape**: With 3 lone pairs and 1 bond, the molecular shape is **linear**. - **Match**: ClF matches with (3) "linear". 2. **Analyze ClF3 (Chlorine Trifluoride)**: - Chlorine again has 7 valence electrons. - In ClF3, chlorine forms 3 bonds with fluorine, using 3 of its electrons. - This leaves 4 electrons, which can be arranged as 2 lone pairs. - **Hybridization**: Here, we have 3 bonds and 2 lone pairs, giving us a total of 5 regions of electron density. This corresponds to **sp³d hybridization**. - **Shape**: With 3 bond pairs and 2 lone pairs, the molecular shape is **T-shaped**. - **Match**: ClF3 matches with (2) "T-shape". 3. **Analyze ClF5 (Chlorine Pentafluoride)**: - Chlorine has 7 valence electrons. - In ClF5, chlorine forms 5 bonds with fluorine, using 5 of its electrons. - This leaves 2 electrons, which can be arranged as 1 lone pair. - **Hybridization**: Here, we have 5 bonds and 1 lone pair, giving us a total of 6 regions of electron density. This corresponds to **sp³d² hybridization**. - **Shape**: With 5 bond pairs and 1 lone pair, the molecular shape is **square pyramidal** (which is a type of octahedral geometry). - **Match**: ClF5 matches with (4) "sp³d²" and (5) "no. of lone pairs one". ### Final Matches: - A: ClF → (3) "linear" - B: ClF3 → (2) "T-shape" - C: ClF5 → (4) "sp³d²" and (5) "no. of lone pairs one" ### Summary of Matches: - A (ClF) → 3 (linear) - B (ClF3) → 2 (T-shape) - C (ClF5) → 4 (sp³d²) and 5 (no. of lone pairs one)

To solve the matching question, we need to analyze the compounds listed in List-I (ClF, ClF3, ClF5) and determine their hybridization, shape, and number of lone pairs. We will then match these properties with the corresponding options in List-II. ### Step-by-Step Solution: 1. **Analyze ClF (Chlorine Monofluoride)**: - Chlorine (Cl) has 7 valence electrons. - In ClF, chlorine forms one bond with fluorine, using 1 of its 7 electrons. - This leaves 6 electrons, which can be arranged as 3 lone pairs. ...
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