Match the following
`{:(,"Set-I (Cl-O bond length",,"Set-II"(A)),((A),HClO,(1),1.64),((B),HClO_(2),(2),1.70),((C),HClO_(3),(3),1.45),((D),HClO_(4),(4),1.57):}`
Correct the matching is

Options

A. `{:(,A,B,C,D),((1),1,2,3,4):}`
B. `{:(,A,B,C,D),((2),2,3,4,1):}`
C. `{:(,A,B,C,D),((3),2,1,4,3):}`
D. `{:(,A,B,C,D),((4),2,1,3,4):}`

Explanation

To solve the problem of matching the bond lengths of Cl-O in various compounds, we will analyze the structures of the compounds given in Set-I and their respective bond lengths in Set-II.

### Step-by-Step Solution:

1. **Identify the Compounds**: The compounds we need to analyze are:
- HClO (Hypochlorous acid)
- HClO₂ (Chlorous acid)
- HClO₃ (Chloric acid)
- HClO₄ (Perchloric acid)

2. **Draw the Structures**:
- **HClO**: The structure is HO-Cl=O (single bond between Cl and O, double bond between Cl and O).
- **HClO₂**: The structure is HO-Cl(=O)-O (one single bond and one double bond).
- **HClO₃**: The structure is HO-Cl(=O)-O(=O) (two double bonds and one single bond).
- **HClO₄**: The structure is HO-Cl(=O)-O(=O)-O(=O) (three double bonds and one single bond).

3. **Analyze Bond Lengths**:
- The bond length of Cl-O will vary based on the number of double bonds present.
- Generally, single bonds are longer than double bonds. The more double bonds present, the shorter the bond length.
- Therefore, we can expect the following order of bond lengths based on the structures:
- HClO (single bond) will have the longest bond length.
- HClO₄ (three double bonds) will have the shortest bond length.
- HClO₂ and HClO₃ will fall in between.

4. **Assign Bond Lengths**:
- HClO: 1.64 Å (longest)
- HClO₂: 1.70 Å
- HClO₃: 1.45 Å
- HClO₄: 1.57 Å (shortest)

5. **Match the Sets**:
- From the analysis, we can match:
- HClO (1.64) → (A)
- HClO₂ (1.70) → (B)
- HClO₃ (1.45) → (C)
- HClO₄ (1.57) → (D)

6. **Final Matching**:
- Therefore, the correct matching is:
- (A) → (1)
- (B) → (2)
- (C) → (3)
- (D) → (4)

### Conclusion:
The correct matching is:
- HClO (1.64) → (A)
- HClO₂ (1.70) → (B)
- HClO₃ (1.45) → (C)
- HClO₄ (1.57) → (D)