[" Q13.Calculate the EMF of the cell."],[Cr|Cr^(3+)(0.1molar)||Fe^(2+)(0.01molar)|Fe],[E^(0)Cr^(3+)|Cr=-.75Volt,E^(0)Fe^(2+1)Fe=-.45Volt]

The EMF of the cell, Cr|Cr^(+3) (0.1M) ||Fe^(+2) (0.01M)|Fe (Given: E^(0) Cr^(+3)|Cr =- 0.75 V, E^(0) Fe^(+2)|Fe =- 0.45 V)

The EMF of the cell, Cr|Cr^(+3) (0.1M) ||Fe^(+2) (0.01M)|Fe (Given: E^(0) Cr^(+3)|Cr =- 0.75 V, E^(0) Fe^(+2)|Fe =- 0.45 V)

Calculate the e.f.m of the cell Cr|Cr^(3+)(0.1M)||Fe^(2+)(0.01M)|Fe [given that E_(Cr^(3+)//Cr)^(@)=-0.75,E_(Fe^(2+)//Fe)^(@)=-0.45V]

Calculate the e.f.m of the cell Cr|Cr^(3+)(0.1M)||Fe^(2+)(0.01M)|Fe [given that E_(Cr^(3+)//Cr)^(@)=-0.75,E_(Fe^(2+)//Fe)^(@)=-0.45V]

What is the potential for the cell Cr|Cr^(3+)(0.1M)||Fe^(2+)(0.01M)|Fe E^(@)Cr^(3+)// Cr=-0.74V , E^(@)Fe^(2+)//Fe=-0.44V

What is the potential for the cell Cr|Cr^(3+)(0.1M)||Fe^(2+)(0.01M)|Fe E^(@)Cr^(3+)// Cr=-0.74V , E^(@)Fe^(2+)//Fe=-0.44V

Calculate the emf of the cell Cr∣ Cr^(3+)(0.1 M)∣∣Fe^(2+) (0.01M)∣Fe (Given: E^(@)Cr^(3+) /Cr =−0.75 volt; E^(@)Fe^(2+) /Fe =−0.45 volt).

Calculate the e.m.f. of the cell, Cr//Cr^(3+)(0.1 M) || Fe^(2+)(0.01 M)//Fe "Given" : E_(Cr^(3+)//Cr)^(@)=-0.75" V ", E_(Fe^(2+)//Fe)^(@)=-0.45" V " "Cell reaction" : 2Cr(s)+3Fe^(2+)(aq) to 2Cr^(3+)(aq)+3Fe(s) {"Hint". E_(cell)=E_(cell)^(@)-(0.0591V)/(6)"log"([Cr^(3+)]^(2))/([Fe^(2+)]^(3)}

Calculate the e.m.f. of the cell at 25^(@)C Cr|Cr^(3+)(0.1M)||Fe^(2+)(0.01M)|Fe Given E_((Cr^(2+)//Cr))^(@)=-0.75V,E_((Fe^(2+)//Fe))^(@)=-0.44