" if "f(x)=sqrt(x^(2)-4),a=2,b=4

Find the value of c, of mean value theorem.when (a) f(x) = sqrt(x^(2)-4) , in the interval [2,4] (b) f(x) = 2x^(2) + 3x+ 4 in the interval [1,2] ( c) f(x) = x(x-1) in the interval [1,2].

If f(x)=(sqrt(x^(2)-4))/(x-4) , what are all the values of x for which f(x) is defined ?

The domain of f(x)=sqrt(({x}^(2)-3{x}+4)/({x}^(2)+3{x}+4))

If f(x)=sqrt(x^(2)-4x+4)+6sqrt(x^(2)) is minimum then the number of values of x is:

Find the domain of f(x)=sqrt((4-x^(2))/([x]+2))

if f(x)=sqrt(x+2sqrt(2x-4))+sqrt(x-2sqrt(2x-4)) then f'(3)+f'(6)= (A) 0 (B) 1 (C) 2 (D) 1/2

If f(x)=sqrt(4-x^(2))+sqrt(x^(2)-1), then the maximum value of (f(x))^(2) is

Find a if f(x)={((sqrt(5x+2)-sqrt(4x+4))/(x-2),x!=2),(a,x=2):} is continuous as x=2