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If m^2 + m'^2 + 2mm' costheta = 1 and n^...

If `m^2 + m'^2 + 2mm' costheta = 1` and `n^2+n'^2+2n n'costheta=1`, `(mn + m' n' + (m n' + m' n) costheta = 0` prove that `m^2 + n^2 = cosec^2theta`

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