cotBcotC+cotCcotA+cotAcotB=1

If A+B+C=pi , show that : tanA+tanB+tanC=tanA.tanB.tanC Hence. Deduce the value of : cotA.cotB+cotB.tanC+cotC.cotA

Prove that- cot(A+B)=(cotA.cotB-1)/(cotA+cotB)

If ((cotAcotB-1))/((cotB+cotA))=x then the value of x is

If A and B are complementary angles, find the value of sqrt((tanAtanB+cotAcotB)/(sinAsecB)-(sin^(2)B)/(cos^(2)A))

If cosA=cosBcosC and A+B+C=pi , then the value of cotBcotC is

The roots of the equation |(1,t-1,1),(t-1,1,1),(1,1,t-1)| = 0 are

If [{:(1, 1), (0,1):}]*[{:(1, 2), (0,1):}]*[{:(1, 3), (0,1):}]cdotcdotcdot[{:(1, n-1), (0,1):}] = [{:(1, 78), (0,1):}] , then the inverse of [{:(1, n), (0,1):}] is

The roots of the equation |{:(x-1,1,1),(1,x-1,1),(1,1,x-1):}|=0 are

The roots of the equation |{:(" "1,t-1," "1),(t-1," "1," "1),(" "1," "1,t-1):}|=0 are