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MODERN PUBLICATION-TRIGONOMETRY-Exercise3(b) Long Answer type Question-I
- ("sin"theta)/(1-costheta)+("tan"theta)/(1+costheta)=secthetacosectheta...
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- (i) (sec theta-cos theta)(cosectheta-"sin"theta)=(1)/("tan"theta+cotth...
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- (i)(1)/(sectheta-"tan"theta)=(1+"sin"theta)/(costheta)=sectheta+"tan"t...
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- (1+cotA+tanA)(sinA-cosA)=(secA)/(cosec^2A)-(cosecA)/(sec^2A)
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- (a) Eliminat theta between the equation: (i)x=h+acostheta,y=k+b"sin"...
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